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प्रश्न
If the velocity of a car is given by V = (150 − 10x)½ m/s. If a car retards their motion by applying brakes then what will be the acceleration?
पर्याय
1 m/s2
2 m/s2
5 m/s2
−5 m/s2
MCQ
उत्तर
−5 m/s2
Explanation:
V = (150 − 10x)½
⇒ `"dV"/"dt" = ("d"(150 - 10"x")^(1//2))/"dt" xx "dx"/"dx"`
`"dV"/"dt" = ("d"(150 - 10"x")^(1//2))/("dx") xx "dx"/"dt"`
⇒ a = `("d"(150 - 10"x")^(1//2))/"dx""V"`
a = `1/2 xx (150 - 10"x")^(-1//2) (-10) xx (150 - 10"x")^(1//2)`
a = −5 m/s2
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