Advertisements
Advertisements
प्रश्न
In a hydroelectric power station, 1000 kg of water is allowed to drop through a height of 100 m in 1 sec. If the conversion of potential energy to electric energy is 60%. Calculate the power output. [Take: g = 10m/sec2]
उत्तर
In a hydroelectric power station:
Mass of water (m) 1000 kg.
Height (h) = 100 m.
Time (t) = 1 sec.
Produced potential energy (P.E.) = mgh = 1000 × 10 × 100 JouIe
= 1000000 joule
Electrical energy = 60% of potential energy
`=60/100xx1000000`
= 600000 joule
Power output = Energy × Time
= 600000 × 1 watt
= 600000 watt
=`600000/1000` kilo-watt
= 600 kilo-watt.
APPEARS IN
संबंधित प्रश्न
Calculate the change in the Kinetic energy of a moving body if its velocity is reduced to 1/3rd of the initial velocity.
Define the term kinetic energy. Give one example of a body which possesses kinetic energy.
Give one relevant example for the following transformation of energy:
Electrical energy to mechanical energy.
State two characteristic which a source of energy must have.
Name three non-renewable sources of energy.
State two uses of solar cells.
Explain the principle of generating electricity from hydro energy.
Write the type of energy possessed in the following case:
A moving cricket ball.
What is dissipation of energy?
A body of mass 0.2 kg falls from a height of 10 m to a height of 6 m above the ground. Find the loss in potential energy taking place in the body. [g = 10ms−2]
