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प्रश्न
In a reaction \[\ce{x + y + z2 -> xyz2}\] identify the Limiting reagent if any, in the following reaction mixture.
200 atoms of x + 200 atoms of y + 50 molecules of z2
उत्तर
Reaction: \[\ce{x + y + z2 -> xyz2}\]
200 atoms of x + 200 atoms of y + 50 molecules of z2.
According to the reaction, 1 atom of x reacts with one atom of y and one molecule of z to give the product.
In case 200 atoms of x, 200 atoms of y react with 50 molecules of z2 (4 part) i.e. 50 molecules of z2 react with 50 atoms of x and 50 atoms of y.
Hence z is the limiting reagent.
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