Question

In an experiment O₃ undergo decomposition as \[\ce{O3 -> O2 + O}\] by the radiations of wavelength 310 Å. The total energy falling on the O₃ gas molecules is 2.4 × 10²⁶ eV and quantum yield of the reaction is 0.2.

The volume strength of the H₂O₂ solution which is obtained from reaction of 1 l H₂O and nascent oxygen [O] obtained from the above reactions is (Assuming no change in volume of H₂O)

\[\ce{H2O + O -> H2O2}\]

[Given: N_a (Avogadro's No.) = 6 × 10²³]

पर्याय

• 1.02

• 22.40

• 2.003

• 5.36

Answer 1

22.40

Explanation:

Assume that n photons strike on O₃ then

n = `(2.4 xx 10^26 xx 1.6 xx 10^-19 xx 310 xx 10^10 " m")/(6.626 xx 10^-34 xx 35 xx 3 xx 10^8 "ms"^-1)`

= 6 × 10²⁴

Since quantum yield = 0.2

It mean’s no. of mole of O atom produced are `(6 xx 10^24 xx 0.2)/(6 xx 10^23)` = 2

Mole of H₂O₂ produced are = 2 mol

Molarity of H₂O₂ = 2 M

and volume strength = (Molarity × 11.2)

= 2 × 11.2

= 22.40