Question

In compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of the compound is 108. Molecular formula of the compound is ______.

पर्याय

• C₂H₆N₂

• C₃H₄N

• C₆H₈N₂

• C₉H₁₂N₃

Answer 1

In compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of the compound is 108. Molecular formula of the compound is C₆H₈N₂.

Explanation:

Element	Percentage (%)	Relative no. of atoms	Simplest ratio of atoms
C	9	`9/12 = 3/4`	3
H	1	`1/1` = 1	4
N	3.5	`3.5/14 = 1/4`	1

Empirical formula = C₃H₄N

(C₃H₄N)_n = 108

n × (12 × 3 + 4 × 1 + 14) = 108

n × (36 + 4 + 14) = 108

n × (54) = 108

n = `108/54`

n = 2

∴ Molecular formula = C₆H₈N₂