Advertisements
Advertisements
प्रश्न
In each of the following, determine whether the given numbers are roots of the given equations or not; 3x2 – 13x – 10 = 0; 5, `(-2)/(3)`
उत्तर
3x2 – 13x – 10 = 0; 5, `(-2)/(3)`
x = 5,
3(5)2 - 13 x 5 - 10
= 75 - 65 - 10
= 75 - 75
= 0
∴ x = 5 is its root
if x = `(-2)/(3)`, then
`3(-2/3)^2 - 13 xx (-2)/(3) - 10`
= `(3 xx 4)/(9) + (26)/(3) - 10`
= `(4)/(3) + (26)/(3) - 10`
= `(30)/(3) - 10`
= 10 - 10
= 0
∴ x = `(-2)/(3)` is also its root.
Hence both 5, `(-2)/(3)` are its roots.
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the roots are real and equal in each of the following equation:
kx2 + kx + 1 = -4x2 - x
Determine the nature of the roots of the following quadratic equation :
x2 -4x + 4=0
Write the discriminant of the quadratic equation (x + 5)2 = 2 (5x − 3).
Find the discriminant of the following equations and hence find the nature of roots: 3x2 – 5x – 2 = 0
Which of the following equations has 2 as a root?
Choose the correct answer from the given four options :
If the equation 3x² – kx + 2k =0 roots, then the the value(s) of k is (are)
Discuss the nature of the roots of the following equation: 3x2 – 7x + 8 = 0
Find the roots of the quadratic equation by using the quadratic formula in the following:
–x2 + 7x – 10 = 0
Find whether the following equation have real roots. If real roots exist, find them.
`x^2 + 5sqrt(5)x - 70 = 0`
Solve for x: `5/2 x^2 + 2/5 = 1 - 2x`.