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प्रश्न
In the given figure, `angle` PQR = 90° , `angle` PQS = 90° , `angle` PRQ = θ and `angle` QPS = θ Write the following trigonometric ratios.
(i) sin θ, cos θ, tan θ
(ii) sin θ , cos θ , tan θ
बेरीज
उत्तर
(i) sin α = `"Opposite side of ∠ PRQ"/"Hypotenuse"` = `"PQ"/"PR"`
cos α = `"Adjacent Side of ∠ PRQ"/"Hypotenuse"` = `"RQ"/"PR"`
tan α = `"Opposite side of ∠ PRQ"/"Adjacent Side of ∠ PRQ"` = `"PQ"/"RQ"`
(ii) sin θ = `"Opposite side of ∠ QPS"/"Hypotenuse"` = `"QS"/"PS"`
cos θ = `"Adjacent Side of ∠ QPS"/"Hypotenuse"` = `"PQ"/"PS"`
tan θ = `"Opposite side of ∠ QPS"/"Adjacent Side of ∠ QPS"` = `"QS"/"PQ"`
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