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प्रश्न
In Newtons’s ring experiment,what will be the order of dark ring which will have double the diameter of 40th dark ring?
उत्तर
For dark ring
`D_n^2 = 4 n λ R`
`D_40^2 = 4 × 40 × λ × R …………(1)`
Let nth be the order of ring whose diameter is double the diameter of 40th dark ring .
`(2D_40)^2 = 4 × n × λ × R…………….(2)`
From equation 1 and 2
`(D_40^2)/(4D_40^2) = 40/ n`
n= 160
Value of n = 160
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