मराठी

In qualitative analysis when H2S is passed through an aqueous solution of salt acidified with dil. HCl, a black precipitate is obtained. On boiling the precipitate with dil. HNO3, it forms a solution - Chemistry

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प्रश्न

In qualitative analysis when \[\ce{H2S}\] is passed through an aqueous solution of salt acidified with dil. \[\ce{HCl}\], a black precipitate is obtained. On boiling the precipitate with dil. \[\ce{HNO3}\], it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives ______.

पर्याय

  • deep blue precipitate of \[\ce{Cu(OH)2}\]

  • deep blue solution of \[\ce{[Cu (NH3)4]^{2+}}\]

  • deep blue solution of \[\ce{Cu(NO3)2}\]

  • deep blue solution of \[\ce{Cu(OH)2 .Cu(NO3)2}\]

MCQ
रिकाम्या जागा भरा

उत्तर

In qualitative analysis when \[\ce{H2S}\] is passed through an aqueous solution of salt acidified with dil. \[\ce{HCl}\], a black precipitate is obtained. On boiling the precipitate with dil. \[\ce{HNO3}\], it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives deep blue solution of \[\ce{[Cu (NH3)4]^{2+}}\].

Black precipitate of copper sulphide is formed which gives blue colour of copper nitrate on boiling with dilute \[\ce{HNO3}\]. When aqueous solution of ammonia is added to it, deep blue colour of

\[\ce{Cu^{2+} + H2S -> \underset{Black}{CuS} + 2H^{+}}\]

\[\ce{CuS + dil. HNO3 -> \underset{Blue}{Cu} (NO3)2}\]

\[\ce{Cu(NO3)2 + 4NH3 -> \underset{Deep blue}{[Cu(NH3)4]^{+}}}\]

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ ९०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 7 The p-block Elements
Multiple Choice Questions (Type - I) | Q 2 | पृष्ठ ९०

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