मराठी

In switching circuit, transistor is in ON state, values of IE and lB are 10 mA and 0.8 mA respectively and RL is 2 kΩ. If VCE is 7.6 V, then VCC is ____________. -

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प्रश्न

In switching circuit, transistor is in ON state, values of IE and lB are 10 mA and 0.8 mA respectively and RL is 2 k`Omega`. If VCE is 7.6 V, then VCC is ____________.

पर्याय

  • 23 V

  • 24 V

  • 25 V

  • 26 V

MCQ
रिकाम्या जागा भरा

उत्तर

In switching circuit, transistor is in ON state, values of IE and lB are 10 mA and 0.8 mA respectively and RL is 2 k`Omega`. If VCE is 7.6 V, then VCC is 26 V.

Explanation:

IE = lB + IC

lC = IE - IB

lC= 10 - 0.8 = 9.2 mA

and VCE = VCC - IC RL

VCC = VCE + IC RL

= 7.6 + (9.2 x 10-3 x 2000)

= 7.6 + 18.4

= 26 V

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Bipolar Junction Transistor (BJT)
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