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प्रश्न
In switching circuit, transistor is in ON state, values of IE and lB are 10 mA and 0.8 mA respectively and RL is 2 k`Omega`. If VCE is 7.6 V, then VCC is ____________.
पर्याय
23 V
24 V
25 V
26 V
MCQ
रिकाम्या जागा भरा
उत्तर
In switching circuit, transistor is in ON state, values of IE and lB are 10 mA and 0.8 mA respectively and RL is 2 k`Omega`. If VCE is 7.6 V, then VCC is 26 V.
Explanation:
IE = lB + IC
lC = IE - IB
lC= 10 - 0.8 = 9.2 mA
and VCE = VCC - IC RL
VCC = VCE + IC RL
= 7.6 + (9.2 x 10-3 x 2000)
= 7.6 + 18.4
= 26 V
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Bipolar Junction Transistor (BJT)
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