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प्रश्न
In the button cells widely used in watches and other devices, the following reaction takes place:
\[\ce{Zn_{(s)} + Ag2O_{(s)} + H2O_{(l)} -> Zn^{2+}_{( aq)} + 2Ag_{(s)} + 2OH^-_{( aq)}}\]
Determine ΔrGΘ and EΘ for the reaction.
उत्तर
\[\ce{E^Θ_{{cell}} = E^Θ_{Ag_2O/Ag} - E^Θ_{{Zn^{2+}/Zn}}}\]
= 0.344 − (−0.76)
= 1.104 V
For the cell reaction, n = 2
∴ ΔrGΘ = `– "nFE"_("cell")^Θ`
∴ ΔrGΘ = – 2 × 96500 × 1.104
= –2.13 × 105 CV mol–1
= –2.13 × 105 J mol–1
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