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प्रश्न
In the figure AB is parallel to DC. Find the value of ∠1 and ∠2. Justify your answer
उत्तर
Given AB || DC
AB and CD are parallel lines Taking CE as transversal we have.
∠1 = 30° ...[∵ alternate interior angles]
Taking DE as transversal
∠2 = 80° ...[∵ alternate interior angles]
∠1 = 30° and ∠2 = 80°
Justification:
CDE is a triangle
∠AEC + ∠CED + ∠DEB = ∠DEC + ∠ECD + ∠CDE
∠1 + 80° = 30° + ∠2
∴ 30° + 80° = 30° + 80°.
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