Advertisements
Advertisements
प्रश्न
In the figure given below, if RS is parallel to PQ, then find the value of ∠y.
उत्तर
In ΔPQR,
∠P + ∠Q + ∠R = 180° ....(angle sum property)
⇒ 4x° + 5x° + 9x° = 180°
⇒ 18x° = 180°
⇒ x = 10
⇒ ∠P = 4x° = 4 x 10° = 40°
∠Q = 5x° = 5 x 10° = 50°
∠QPR = ∠PRS ....(Alternate angles)
And, ∠QPR = 40°
∠PRS = 40°
By exterior angle property,
∠PQR + ∠QPR = ∠PRS + y°
⇒ 40° + 50° = 40° + y°
⇒ y = 50°
APPEARS IN
संबंधित प्रश्न
In a triangle PQR, ∠P + ∠Q = 130° and ∠P + ∠R = 120°. Calculate each angle of the triangle.
The angles of a triangle are (x + 10)°, (x + 30)° and (x - 10)°. Find the value of 'x'. Also, find the measure of each angle of the triangle.
In a triangle PQR, the internal bisectors of angles Q and R meet at A and the external bisectors of the angles Q and R meet at B. Prove that: ∠QAR + ∠QBR = 180°.
Use the given figure to show that: ∠p + ∠q + ∠r = 360°.
In a triangle ABC. If D is a point on BC such that ∠CAD = ∠B, then prove that: ∠ADC = ∠BAC.
In a triangle ABC, if the bisectors of angles ABC and ACB meet at M then prove that: ∠BMC = 90° + `(1)/(2)` ∠A.
If bisectors of angles A and D of a quadrilateral ABCD meet at 0, then show that ∠B + ∠C = 2 ∠AOD
If the angles of a triangle are in the ratio 2: 4: 6; show that the triangle is a right-angled triangle.
In a triangle, the sum of two angles is 139° and their difference is 5°; find each angle of the triangle.
In a right-angled triangle ABC, ∠B = 90°. If BA and BC produced to the points P and Q respectively, find the value of ∠PAC + ∠QCA.