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प्रश्न
In the figure, the optical fibre is l = 2 m long and has a diameter of d = 20 µm. If a ray of light is incident on one end of the fiber at angle θ1 = 40°, the number of reflections it makes before emerging from the other end is close to ______.
(Refractive index of fiber is 1.31 and sin40° = 0.64)
पर्याय
55000
66000
45000
57000
उत्तर
In the figure, the optical fibre is l = 2 m long and has a diameter of d = 20 µm. If a ray of light is incident on one end of the fiber at angle θ1 = 40°, the number of reflections it makes before emerging from the other end is close to 57000.
Explanation:
Given: Optical fibre length, l = 2 m, the diameter of the fibre, d = 20 µm, Angle of incidence at the fiber's entrance θ1 = 40°, the refractive index of fibre, μ2 = 1.31.
To find:
The total number of reflections inside the fibre.
Snell's law:
`mu_1/mu_2 = (sintheta_2)/(sin40^circ)`, (The refractive index of air is µ1.)
`sintheta_2 = 1/1.31 sin40^circ`,
θ2 = 29.39
θ = 90 - θ2 = 90 - 29.39 = 60.6 (θ as shown in the diagram)
`tantheta = tan60.6 = x/d` (x is labelled in the diagram.)
`x = (20 xx 10^-6)`tan60.6 = 35.5µm
Number of total reflections;
`n = 1/x = (2m)/(35.5mum) = 56338.`