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प्रश्न
In the given figure, a = 15 m/s2 represents the total acceleration of a particle moving in the clockwise direction on a circle of radius R = 2.5 m at a given instant of time. The speed of the particle is ______.
पर्याय
6.2 m/s
4.5 m/s
5.0 m/s
5.7 m/s
MCQ
रिकाम्या जागा भरा
उत्तर
In the given figure, a = 15 m/s2 represents the total acceleration of a particle moving in the clockwise direction on a circle of radius R = 2.5 m at a given instant of time. The speed of the particle is 5.7 m/s.
Explanation:
Tan θ = `("dV"//"dt")/("V"^2//"R")`
Tan 30° = `1/sqrt3=("dV"//"dt")/("V"^2//"R")`
dV = `1/sqrt3xx"V"^2/"R"`
a = 15 = `sqrt(("dV"/"dt")^2+("V"^2/"R")^2)`
15 = `sqrt(4/3("V"^2/"R")^2)`
15 = `2/sqrt3("V"^2/"R")`
= `2/sqrt3xx"V"^2/2.5`
⇒ V2 = `(15xxsqrt3xx2.5)/2`
= 32.476 = 5.7 m/s
shaalaa.com
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