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प्रश्न
In the given figure, AB || CD, AF || ED, ∠AFC = 68° and ∠FED = 42°. Find ∠EFD.
बेरीज
उत्तर
Since, AF || ED and FD is a transversal.
∴ ∠3 = 68° ......(i) [Corresponding angles]
Now, AB || CD and ED is a transversal.
∴ (∠2 + 42°) + ∠3 = 180° ......[Co-interior angles]
⇒ ∠2 = 180° – 42° – 68° ......[Using (i)]
⇒ ∠2 = 70° ......(ii)
Also, AB || CD and EF is a transversal.
∴ ∠1 = ∠2 ......[Alternate interior angles]
⇒ ∠1 = 70° ......[Using (ii)]
Thus, ∠EFD = 70°
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