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प्रश्न
In the given figure, if AB || CD, ∠APQ = 50° and ∠PRD = 127°, find x and y.
बेरीज
उत्तर
We have AB || CD and PQ is a transversal.
∴ ∠APQ = ∠PQR ...[Alternate interior angles]
= 50° = x ...[∵ ∠APQ = 50° (given)]
Again, AB || CD and PR are transversal.
∴ ∠APR = ∠PRD ...[Alternate interior angles]
= ∠APR = 127° ...[∵ ∠PRD = 127° (given)]
= ∠APQ + ∠QPR = 127°
= 50° + y = 127° ...[∵ ∠APQ = 50° (given)]
= y = 127° − 50°
= y = 77°
Thus, x = 50° and y = 77°.
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