Question

In the ground state of atomic Fe (Z = 26), the spin-only magnetic moment is ______ × 10^-1 BM.
(Round off to the nearest integer).

[Given: `sqrt3 = 1.73, sqrt2 = 1.41`]

पर्याय

• 86

• 49

• 63

• 41

Answer 1

In the ground state of atomic Fe (Z = 26), the spin-only magnetic moment is 49 × 10^-1 BM.

Explanation:

Fe (Z = 26) ⇒ [Ar] 3d⁶ 4s²

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Number of unpaired electrons = 4

`because mu = sqrt("n"("n + 2"))`BM

`therefore mu = sqrt(4(4 + 2))`

`therefore mu = sqrt24` BM

= 4.89 ≈ 49 × 10^-1 BM