Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x:
`sec^2 x/5 + 18 cos2x + 10sec(5x + 3) tan(5x + 3)`
उत्तर
`int [sec^2 x/5 + 18 cos2x + 10sec(5x + 3) tan(5x + 3)] "d"x`
= `int sec^2 x/5 "d"x + 18 int cos 2x "d"x + 10 int sec(5x + 3) tan(5x + 3) "d"x`
= `(tan x/5)/(1/5) + 18 ((sin 2x)/2) + 10 (sec(5x + 3))/5 + "c"`
= `5 tan (x/5)/5 + 9 sin 2x + 2sec (5x + 3) + "c"`
APPEARS IN
संबंधित प्रश्न
Integrate the following with respect to x:
`(x + 4)^5 + 5/(2 - 5x)^4 - "cosec"^2 (3x - 1)`
Integrate the following with respect to x:
`4 cos(5 - 2x) + 9"e"^(3x - 6) + 24/(6 - 4x)`
Integrate the following with respect to x:
`8/sqrt(1 - (4x)^2) + 27/sqrt(1 - 9x^2) - 15/(1 + 25x^2)`
Integrate the following with respect to x:
`6/(1 + (3x + 2)^2) - 12/sqrt(1 - (3 - 4x)^2`
Integrate the following with respect to x:
`1/3 cos(x/3 - 4) + 7/(7x + 9) + "e"^(x/5 + 3)`
