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प्रश्न
Justify whether it is true to say that the following are the nth terms of an AP.
3n2 + 5
पर्याय
True
False
उत्तर
This statement is False.
Explanation:
Here,
an = 3n2 + 5
Put n = 1,
a1 = 3(1)2 + 5
= 8
Put n = 2,
a2 = 3(2)2 + 5
= 3(4) + 5
= 17
Put n = 3,
a1 = 3(3)2 + 5
= 3(9) + 5
= 27 + 5
= 32
So, the list of number becomes 8, 17, 32,...
Here, a2 – a1 = 17 – 8 = 9
a3 – a2 = 32 – 17 = 15
∴ a2 – a1 ≠ a3 – a2
Since, the difference of the successive term is not same.
So, it does not form an AP.
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