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प्रश्न
Let g(x) = cosx2, f(x) = `sqrt(x)`, and α, β (α < β) be the roots of the quadratic equation 18x2 – 9πx + π2 = 0. Then the area (in sq. units) bounded by the curve y = (gof)(x) and the lines x = α, x = β and y = 0, is ______.
पर्याय
`1/2(sqrt(3) + 1)`
`1/2(sqrt(3) - sqrt(2))`
`1/2(sqrt(2) - 1)`
`1/2(sqrt(3) - 1)`
MCQ
रिकाम्या जागा भरा
उत्तर
Let g(x) = cosx2, f(x) = `sqrt(x)`, and α, β (α < β) be the roots of the quadratic equation 18x2 – 9πx + π2 = 0. Then the area (in sq. units) bounded by the curve y = (gof)(x) and the lines x = α, x = β and y = 0, is `underlinebb(1/2(sqrt(3) - 1))`.
Explanation:
Here, 18x2 – 9πx + π2 = 0
`\implies` (3x – π) (6x – π) = 0
`\implies` α = `π/6`, β = `π/3`
Also, gof(x) = cosx
∴ Required area = `int_(π//6)^(π//3) cosxdx = (sqrt(3) - 1)/2`
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