Question

Let `y = f(x)` be the equation of the curve, then equation of normal is

पर्याय

• `y - y_o = - 1/m (x - m)`

• `x - x_o + m(y - y_0)` = 0

• `((dy)/(dx))Δx`

• Both `y - y_o = - 1/m (x - m)` and `x - x_o + m(y - y_0)` = 0

Answer 1

Both `y - y_o = - 1/m (x - m)` and `x - x_o + m(y - y_0)` = 0

Explanation:

Let `y(x)` be the equation of the curve, then education of the normal is

`y - y_o = - 1/m`

or `x - x_o + m(y - y_o)` = 0

Where m = Slope of the tangent

`[(dy)/(dx)]_(x_o * y_o) = f^'(x_o)`