Advertisements
Advertisements
प्रश्न
ln, a Wheatstone network, P = Q = R = 8 `Omega` and S is 10 `Omega`. The required resistance to be connected to S so that network is balanced is ______.
पर्याय
40 `Omega` in parallel
48 `Omega` in parallel
32 `Omega` in parallel
24 `Omega` in parallel
MCQ
रिकाम्या जागा भरा
उत्तर
ln, a Wheatstone network, P = Q = R = 8 `Omega` and S is 10 `Omega`. The required resistance to be connected to S so that network is balanced is 40 `Omega` in parallel.
Explanation:
S = X `abs` 10 = 8 `Omega`
`therefore (10"X")/(10 + "X") = 8`
`therefore 10"X"` = 80 + 8X
`therefore 2"X" = 80`
`therefore "X" = 40 Omega`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
