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प्रश्न
Mrs. Geeta deposited Rs. 350 per month in a bank for 1 year and 3 months under the Recurring Deposit Scheme. If the maturity value of her deposits is Rs. 5,565; find the rate of interest per annum.
उत्तर
Installment per month (P) = Rs. 350
Number of months (n) = 15
Let rate of interest (r) = r% p.a.
∴ `S.I. = P xx (n(n + 1))/(2 xx 12) xx r/100`
= `350 xx (15(15 + 1))/(2 xx 12) xx r/100`
= `350 xx 240/24 xx r/100`
= Rs. (35)r
Maturity value = Rs. (350 × 15) + Rs. (35)r
Given maturity value = Rs. 5,565
Then Rs. (350 × 15) + Rs. (35)r = Rs. 5,565
`=>` 35r = Rs. 5,565 – Rs. 5,250
`=>` r = `315/35` = 9%
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संबंधित प्रश्न
A page from the savings bank account of Mrs Ravi is given below.
| Date | Particulars | Withdrawal (Rs.) |
Deposit (Rs.) | Balance (Rs.) |
| April 3rd 2006 | B/F | 6000 | ||
| April 7th | By cash | 2300 | 8300 | |
| April 15th | By cheque | 3500 | 11800 | |
| May 20th | To self | 4200 | 7600 | |
| June 10th | By cash | 5800 | 13400 | |
| June 15th | To self | 3100 | 10300 | |
| August 13th | By cheque | 1000 | 11300 | |
| August 25th | To self | 7400 | 3900 | |
| September 6th 2006 |
By cash | 2000 | 5900 |
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| ...... | 5% | ...... | 6000 | 18000 |
