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प्रश्न
Observe the following table and find the Mean:
Assumed mean A = 300
Class | Class mark | di = xi – A | Frequency | Frequency × Deviation |
xi | di = xi – 300 | fi | fi di | |
200 – 240 | 220 | – 80 | 5 | – 400 |
240 – 280 | 260 | – 40 | 10 | – 400 |
280 – 320 | 300 `rightarrow` A | 0 | 15 | 0 |
320 – 360 | 340 | 40 | 12 | 480 |
360 – 400 | 380 | 80 | 8 | 640 |
Total | `sumf_i` = 50 | `sumf_i d_i` = 320 |
बेरीज
उत्तर
`sum fi = 50`
`sum fi di = 320`
Assumed mean = A = 300
`overline d = (sum fi di)/ (sum fi)`
= `320/50`
= 6.4
∴ Mean `overline X = A + overline d`
= 300 + 6.4
= 306.4
Mean = 306.4
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Method of Finding Mean for Grouped Data: Deviation Or Assumed Mean Method
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संबंधित प्रश्न
Calculate the mean of the following distribution using Assumed Mean Method
Class Interval | 0 − 10 | 10 − 20 | 20 − 30 | 30 − 40 | 40 − 50 |
Frequency | 5 | 7 | 15 | 28 | 8 |