Question

Of the five isomeric hexanes, the isomer which can give two monochlorinated compounds is ______.

पर्याय

• 2-methylpentane

• 2, 2-dimethylbutane

• 2, 3-dimethylbutane

• n-hexane

Answer 1

Of the five isomeric hexanes, the isomer which can give two monochlorinated compounds is 2, 3-dimethylbutane.

Explanation:

\[\begin{array}{cc}
\phantom{..}\ce{\overset{1°}{C}H3}\phantom{...}\ce{\overset{1°}{C}H3}\phantom{.}\\
\phantom{}|\phantom{......}|\phantom{..}\\
\phantom{}\ce{\overset{1°}{C}H3 - \underset{3°}{C}H - \underset{3°}{C}H - \overset{1°}{C}H3}
\end{array}\]

It will produce only two monochlorinated compounds since it includes only two types of H-atoms.

\[\begin{array}{cc}
\phantom{.......}\ce{CH3}\phantom{..}\ce{CH3}\phantom{.}\\
\phantom{....}|\phantom{......}|\phantom{}\\
\phantom{}\ce{\underset{1-Chloro-2, 3-dimethylbutane}{Cl - CH2 - CH - CH - CH3}}
\end{array}\]

and

\[\begin{array}{cc}
\phantom{...}\ce{CH3}\phantom{.}\ce{CH3}\phantom{.....}\\
\phantom{..}|\phantom{....}|\phantom{.......}\\
\ce{CH3 - C - CH - CH3}\phantom{....}\\
|\phantom{..........}\\
\ce{\underset{2-Chloro-2,3-dimethylbutane}{Cl}}\phantom{.........}
\end{array}\]