Advertisements
Advertisements
प्रश्न
On what sum will the difference between compound interest and the simple interest for 3 years at 12% be Rs 1,123.20?
उत्तर
P = x ; t = 3 years ; r = 12 % For S.I.:
I = `("P" xx "r" xx "t")/100`
`= ("x" xx 12 xx 3)/100`
`= (9"x")/25`
For C.I. :
C.I. = `"P" (1 + "r"/100)^"t" - "P"`
`= "x" (1 + 12/100)^3 - "x"`
`= "x" (1 + 3/25)^3 - "x"`
= (x × 1.12 × 1.12 × 1.12) - x
=1. 404928x - x
= 0.404928 x
Given C.1.- S. I. = Rs 22.50
⇒ 0.404928 x - `(9"x")/25` = Rs 1123.20
⇒ 0.404928 x - 0.36 x = Rs 1123.20
⇒ 0.044928 x = Rs 1123.20
⇒ x = Rs 25000
Hence, sum = Rs 25,000
APPEARS IN
संबंधित प्रश्न
The simple interest and the compound interest on a certain sum of money for 2 years at the same rate of interest are Rs 8,000 and Rs 8,640 respectively. Calculate the rate of interest and the sum.
Find the difference between the compound interest and the simple interest in 3 years on Rs 15,000 at 8% p.a. compounded yearly.
On what sum will the difference between compound interest and the simple interest for 2 years at `7 1/2` % be Rs 22.50 ?
In a factory the production of scooters rose to 46,305 from 40,000 in 3 years. Find the annual rate of growth of the production of scooters.
The present population of a town is 1,
0/o per annum 1, 15,200. If it increases at the rate of `6 2/3` % per annum find
Its population 2 years ago.
The population of a city is 24,000. In the next 3 years it will be 27,783. Find the rate of growth of the population.
A new car is purchased for Rs 4, 00,000 .Its value depreciates at the rate of 10% per annum. What will be its value after 4 years?
A building worth Rs 1, 33,100 is constructed on a plot of land worth Rs 72,900. After how many years will the values of both be same, if the land appreciates at 10% p.a. and the building depreciates at 10% p.a.?
Find the Compound Interest on Rs. 2,000 for 3 years at 15% per annum Compounded annually.
A sum of money amounts to ₹ 2,240 at 4 % p.a., simple interest in 3 years. Find the interest on the same sum for 6 months at 3`(1)/(2)`% p.a.