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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 6

Out of 50 Identical Articles, 36 Are Broken. Find the Fraction Of: (I) the Total Number of Articles and the Articles Broken. (Ii) the Remaining Articles and the Total Number of Articles. - Mathematics

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प्रश्न

Out of 50 identical articles, 36 are broken. Find the fraction of:
(i) The total number of articles and the articles broken.
(ii) The remaining articles and the total number of articles.

बेरीज

उत्तर

Total number of articles = 50
Number of articles broken = 36
Remaining articles = 50 – 36 = 14
Now,

(i) The fraction of the total number of articles and articles broken = `50/36`

= `(50÷2)/(36÷2)=25/18`

(ii) The fraction between the remaining articles and total numbers of articles

= `14/50=(14÷2)/(50÷2)=7/25`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Fractions - Exercise 14 (B)

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सेलिना Mathematics [English] Class 6
पाठ 14 Fractions
Exercise 14 (B) | Q 9
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