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प्रश्न
Plot the following points and write the name of the figure obtained by joining them in order:
P(– 3, 2), Q(– 7, – 3), R(6, – 3), S(2, 2)
उत्तर
Let X’ OX and Y’ OY be the coordinate axes and mark point on it. Here, point P(– 3, 2) lies in II quadrant, Q(– 7, – 3) lies in III quadrant, R(6, – 3) lies in IV quadrant and S(2, 2) lies in I quadrant. Plotting the points on the graph paper, the figure obtained is trapezium PQRS.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(0, 0)
Plot the following point on the graph paper:
(−3, 2)
Plot the following points in the coordinate plane. Join them in order. What type of geometrical shape is formed?
(−3, 3) (2, 3) (−6, −1) (5, −1)
Plot the following point in a graph sheet.
E(0, −5)
Plot the following point in a graph sheet.
G(7, −4)
Find the quadrants without plotting the point on a graph sheet.
(−8, 0)
Plot the following points and check whether they are collinear or not:
(1, 1), (2, – 3), (– 1, – 2)
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
From the figure, answer the following:
Write the points whose abscissa is – 5.
Plot the points A(1, – 1) and B(4, 5). Draw a line segment joining these points. Write the coordinates of a point on this line segment between the points A and B.
