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प्रश्न
Predict the product of electrolysis in the following:
An aqueous solution of AgNO3 with silver electrodes.
उत्तर
AgNO3 ionizes in aqueous solutions to form Ag+ and `"NO"_3^(-)` ions.
On electrolysis, either Ag+ ions or H2O molecules can be reduced at the cathode. But the reduction potential of Ag+ ions is higher than that of H2O.
\[\ce{Ag+_{ (aq)} + e- -> Ag_{(s)}};\] E° = + 0.80 V
\[\ce{2H_2O_{(l)} + 2e- -> H_{2(g)} + 2OH^-_{ (aq)}}\]; E° = - 0.83 V
Hence, Ag+ ions are reduced at the cathode. Similarly, Ag metal or H2O molecules can be oxidized at the anode. But the oxidation potential of Ag is higher than that of H2O molecules.
\[\ce{Ag_{(s)} -> Ag+_{(aq)} + e-}\]; E° = - 0.80 V
\[\ce{2H_2O_{(l)} -> O_{2(g)} + 4H+_{ (aq)} + 4e-}\]; E° = -1.23 V
Therefore, Ag metal gets oxidized at the anode.
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