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प्रश्न
Q 10.1
बेरीज
उत्तर
Required sum = 4 + 44 + 444 +........... upto n terms
= 4(1 + 11 + 111 +........... upto n terms)
=`4/9`(9 + 99 + 999 +........... upto n terms)
=`4/9`[(10 - 1) + (100 - 1) + (1000 - 1) +........... upto n terms)
=`4/9`[(10 + 102 + 103 +........... upto n terms)-(1 + 1 + 1 +........... upto n terms)]
=`4/9[(10(10^n-1))/(10-1)-n]`
=`4/9[10/9(10^n-1)-n]`
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Geometric Progression - Finding Sum of Their First ‘N’ Terms
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