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प्रश्न
Q 10
बेरीज
उत्तर
Sum of an infinite G.P. = S = `80/9`
common ratio = r = `-4/5` .........`[|-4/5|=4/5<1]`
`therefore a/(1-r)=80/9`
⇒ `a/(1-(-4/5))=80/9`
⇒ `(5a)/9=80/9`
⇒ 5a = 80
⇒ a = 16 = First term
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Geometric Progression - Finding Sum of Their First ‘N’ Terms
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