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प्रश्न
Q 1.3
बेरीज
उत्तर
Given G.P. : `1/3 + 1/3^2 + 1/3^3 +`........
Here,
first terms, a = `1/3`
common ratio, r =`(1/3^2)/(1/3)=1/3 (|r| = |1/3|=1/3<1)`
∴ Required sum =`a/(1-r)=(1/3)/(1-1/3)=(1/3)/(2/3)=1/2`
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Geometric Progression - Finding Sum of Their First ‘N’ Terms
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