Advertisements
Advertisements
प्रश्न
Q 2
बेरीज
उत्तर
Let `"a"^(1/"x")="b"^(1/"y")="c"^(1/"z")="k"`
`=> "a"^(1/"x")="k", "b"^(1/"y")="k"` and `"c"^(1/"z") = "k"`
⇒ a = kx, b = ky and c = kz
Given that a, b, c are in G.P.
⇒ b2 = ac
⇒ (ky)2 = kx x kz
⇒ k2y = kx+z
⇒ 2y = x + z
⇒ x, y, z are in A.P.
shaalaa.com
Simple Applications - Geometric Progression
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
