Question

Range of projectile will be maximum when angle of projectile is

पर्याय

• 30°

• 45°

• 60°

• 90°

Answer 1

45°

Explanation:

Range of projectile motion = `(mu^2 sin 2theta)/g`

For maximum range ⇒ sin 2θ = 1 = sin 90°

∴ θ  = 45°