Advertisements
Advertisements
प्रश्न
Rekha borrowed Rs. 40,000 for 3 years at 10% per annum compound interest. Calculate the interest paid by her for the second year.
उत्तर
For 1st year
Principal = Rs.40,000, Rate = 10%, Time = 1 year
∴ Interest =`(40,000xx10xx1)/100`
= 400 × 10
= Rs.4000
∴ Amount at the end of 1st year = Rs. (40,000 + 4000) = Rs.44,000
For 2nd year
P = Rs.44,000, R = 10%, T = 1 year
∴ Interest = Rs.`(44,000xx10xx1)/100`
= 440 × 10
= Rs.4400
Thus interest earned in the second year = Rs.4400
APPEARS IN
संबंधित प्रश्न
Calculate the amount and compound interest on Rs 10800 for 3 years at `12 1/2` % per annum compounded annually.
Calculate the amount and compound interest on Rs 18000 for `2 1/2` years at 10% per annum compounded annually.
In what time will Rs 1000 amount to Rs 1331 at 10% per annum, compound interest?
The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?
A certain sum of money is put at compound interest, compounded half-yearly. If the interest for two successive half-years are Rs. 650 and Rs. 760.50; find the rate of interest.
Ramesh invests Rs. 12,800 for three years at the rate of 10% per annum compound interest. Find:
(i) the sum due to Ramesh at the end of the first year.
(ii) the interest he earns for the second year.
(iii) the total amount due to him at the end of the third year.
Saurabh invests Rs. 48,000 for 7 years at 10% per annum compound interest. Calculate:
(i) the interest for the first year.
(ii) the amount at the end of second year.
(iii) the interest for the third year.
A certain sum of money invested for 5 years at 8% p.a. simple interest earns an interest of ₹ 12,000. Find:
(i) the sum of money.
(ii) the compound interest earned by this money in two years and at 10% p.a. compound interest.
Find the amount and the compound interest payable annually on the following :
Rs.25000 for 1`(1)/(2)` years at 10% per annum.
Depreciation value is calculated by the formula, `"P"(1 - "r"/100)^"n"`
