Advertisements
Advertisements
प्रश्न
Resolve into Partial Fractions:
`(5x + 7)/((x-1)(x+3))`
उत्तर
`(5x + 7)/((x-1)(x+3)) = "A"/(x-1) + "B"/(x+3)`
⇒ 5x + 7 = A(x + 3) +B(x - 1) ...(1)
Substituting x = 1 in (1) we get,
5(1) + 7 = A(1 + 3) +B(1 - 1)
⇒ 12 = A(4)
⇒ `12/4` = 3
⇒ A = 3` .....(1)
Substituting x = - 3 in (1) we get,
5(-3) + 7 = A(- 3 + 3) +B(- 3 - 1)
⇒ - 8 = B(-4)
⇒ B = `(-8)/(-4)`
⇒ B = 2
∴ `(5x + 7)/((x-1)(x+3)) = 3/(x - 1) + 2/(x + 3)`
APPEARS IN
संबंधित प्रश्न
Resolve into partial fraction for the following:
`(4x + 1)/((x - 2)(x + 1))`
Resolve into partial fraction for the following:
`1/((x - 1)(x + 2)^2)`
Resolve into partial fraction for the following:
`1/(x^2 - 1)`
Resolve into partial fraction for the following:
`(x - 2)/((x + 2)(x - 1)^2)`
Resolve into partial fraction for the following:
`(x^2 - 3)/((x + 2)(x^2 + 1))`
Resolve into a partial fraction for the following:
`1/((x^2 + 4)(x + 1))`
Resolve into Partial Fractions:
`(x - 4)/(x^2 - 3x + 2)`
Decompose into Partial Fractions:
`(6x^2 - 14x - 27)/((x + 2)(x - 3)^2)`
Decompose into Partial Fractions:
`(5x^2 - 8x + 5)/((x - 2)(x^2 - x + 1))`
If `(kx)/((x + 4)(2x - 1)) = 4/(x + 4) + 1/(2x - 1)` then k is equal to:
