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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. - Algebra

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प्रश्न

Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. For this complete the following activity.

उत्तर

It is given that,
Principal (P) = Rs 1000
Rate (R) = 10%
Simple interest (S.I.) =\[\frac{P \times R \times T}{100}\]

Simple interest after an year = \[\frac{1000 \times 10 \times 1}{100} = Rs 100\]

Simple interest after 2 years = \[\frac{1000 \times 10 \times 2}{100} = Rs 200\]

Simple interest after 3 years = \[\frac{1000 \times 10 \times 3}{100} = Rs 300\]

Hence, the total interest amount is in A.P. i.e. 100, 200, 300,....

Here,
a = 100
d = 100
Now,

\[a_n = a + \left( n - 1 \right)d\]

\[ a_{20} = a + \left( 20 - 1 \right)d\]

\[ = 100 + 19\left( 100 \right)\]

\[ = 100 + 1900\]

\[ = 2000\]

Hence, the interest amount after 20 years is Rs 2000.

 
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पाठ 3: Arithmetic Progression - Problem Set 3 [पृष्ठ ८०]

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बालभारती Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board
पाठ 3 Arithmetic Progression
Problem Set 3 | Q 14 | पृष्ठ ८०

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