Advertisements
Advertisements
प्रश्न
Rs. 9000 were divided equally among a certain number of persons. Had there been 20 more persons, each would have got Rs. 160 less. Find the original number of persons.
उत्तर
Let the original number of persons be x.
Then, by the given information,
`9000/x-160=900/(x+20)`
`(9000-160x)/x=9000/(x+20)`
(x + 20)(9000 - 160x) = 9000x
9000x - 160x2 + 180000 - 3200x = 9000x
160x2 - 180000 + 3200x = 0
x2 - 1125 + 20x = 0
x2 - 1125 + 20x + 100 = 100
(x + 10)2 = 1225
x + 10 = 35
x = 35 - 10
x = 25
Thus, the original number of persons is Rs 25.
APPEARS IN
संबंधित प्रश्न
Solve for x: `(x-3)/(x-4)+(x-5)/(x-6)=10/3; x!=4,6`
Find the whole numbers which when decreased by 20 is equal to 69 times the reciprocal of the members.
There are three consecutive integers such that the square of the first increased by the product of the first increased by the product of the others the two gives 154. What are the integers?
Sum of two numbers is 16. The sum of their reciprocals is 1/3. Find the numbers.
The length of a hall is 5 m more than its breadth. If the area of the floor of the hall is 84 m2, what are the length and breadth of the hall?
A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.
Solve the following quadratic equation by factorisation.
\[25 m^2 = 9\]
A person was given Rs. 3000 for a tour. If he extends his tour programme by 5 days, he must cut down his daily expenses by Rs. 20. Find the number of days of his tour programme.
Solve the following quadratic equation by factorization method.
3p2 + 8p + 5 = 0
Is 0.2 a root of the equation x2 – 0.4 = 0? Justify
