Question

Sand is being dropped from a stationary dropper at a rate of 0.5 kgs^-1 on a conveyor belt moving with a velocity of 5 ms^-1. The power needed to keep belt moving with the same velocity will be ______.

पर्याय

• 1.25 W

• 2.5 W

• 6.25 W

• 12.5 W

Answer 1

Sand is being dropped from a stationary dropper at a rate of 0.5 kgs^-1 on a conveyor belt moving with a velocity of 5 ms^-1. The power needed to keep belt moving with the same velocity will be 12.5 W.

Explanation:

`"F"_"thrust" = "V"_"rel""dm"/"dt"`

= 5 × 0.5

= 2.5 N

So, Power = Force × Velocity

= 2.5 × 5

= 12.5 watt.