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प्रश्न
Show that `tan^-1 1/2 - tan^-1 1/4 = tan^-1 2/9`.
उत्तर
LHS = `tan^-1 1/2 - tan^-1 1/4`
`= tan^-1 [(1/2 - 1/4)/(1 + (1/2)(1/4))]`
`= tan^-1 ((4 - 2)/(8 + 1))`
`= tan^-1 (2/9)` = RHS.
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