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प्रश्न
Silver crystallises in fcc structure, if edge length of unit cell is 316.5 pm. What is the radius of silver atom?
पर्याय
121.91 pm
111.91 pm
137.04 pm
158.25 pm
MCQ
उत्तर
111.91 pm
Explanation:
Given,
Edge length of unit cell (a) = 316.5 pm
For fcc we know,
Radius (r) = `"a"/(2sqrt2)`
`= 316.5/(2sqrt2)`pm
`= 158.25/1.414` pm
= 111.91 pm
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Cubic System
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