Question

Simplify.

${\displaystyle 2\sqrt{48}-\sqrt{75}-\frac{1}{\sqrt{3}}}$

Answer 1

${\displaystyle 2\sqrt{48}-\sqrt{75}-\frac{1}{\sqrt{3}}}$

${\displaystyle =2\sqrt{16\times 3}-\sqrt{25\times 3}-\frac{1}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}}$

${\displaystyle =2\times 4\sqrt{3}-5\sqrt{3}-\frac{\sqrt{3}}{3}}$

${\displaystyle =8\sqrt{3}-5\sqrt{3}-\frac{\sqrt{3}}{3}}$

${\displaystyle =3\sqrt{3}-\frac{\sqrt{3}}{3}}$

${\displaystyle =\frac{9\sqrt{3}-\sqrt{3}}{3}}$

${\displaystyle =\frac{8}{3}\sqrt{3}}$