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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Simplify: 5a – 6a – {9a – (10a – Bar("4a" - "3a"))} - Mathematics

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प्रश्न

Simplify: 5a – [6a – {9a – (10a – `bar("4a" - "3a"))}]`

बेरीज

उत्तर

5a – [6a – {9a – (10a – `bar("4a" - "3a"))}]`

= 5a – [6a – {9a – (10a – 4a + 3a)}]

= 5a – [6a – {9a – 10a + 4a – 3a}]

= 5a- [6a – 9a + 10a – 4a + 3a]

= 5a – 6a + 9a – 10a + 4a – 3a

= 5a + 9a + 4a – 6a – 10a – 3a

= 18a – 19a

= – a

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पाठ 11: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (F)

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सेलिना Concise Mathematics [English] Class 7 ICSE
पाठ 11 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (F) | Q 28
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