Question

Six very long insulated copper wires are bound together to form a cable. The currents carried by the wires are I₁ = +10 A, I₂ = -12 A, I₃ = +10A, I₄ = +8 A, I₅ = -11 A and I₆ = 19 A. The magnetic induction at a perpendicular distance of 20 cm from the cable is ______.

पर्याय

• 375 µT

• 40 µT

• 3.35 µT

• 24 µT

Answer 1

Six very long insulated copper wires are bound together to form a cable. The currents carried by the wires are I₁ = +10 A, I₂ = -12 A, I₃ = +10A, I₄ = +8 A, I₅ = -11 A and I₆ = 19 A. The magnetic induction at a perpendicular distance of 20 cm from the cable is 24 µT.

Explanation:

Net current I =  I₁+ I₂ + I₃ + I₄ = +I₅ + I₆ 

= 10 - 12 + 10 + 8 - 11 + 19

=24 A

Magnetic induction B = `(µ_0 "I")/(2pi`"R")`

Here R = 20 cm = 0.2 m

` therefore "B" = (4pi xx 10^-7 xx 24)/(2pixx0.2) = 24 xx 10^-6 "T" = 24 µ"T"`