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प्रश्न
Solid ammonium dichromate decomposes as:
\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]
If 63 g of ammonium dichromate decomposes. Calculate the volume of N2 evolved at STP.
उत्तर १
Solid ammonium dichromate decomposes as:
\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]
252 g of ammonium dichromate gives 22.4 dm3 of N2
63 g of ammonium dichromate gives `(63 xx 22.4)/252`
= 5.6 L
उत्तर २
The volume of N2 evolved at STP = `22.4/4`
= 5.6 litres
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