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प्रश्न
Solve 3x – 2 ≡ 0 (mod 11)
उत्तर
3x – 2 ≡ 0 (mod 11)
3x – 2 = 11 n for some integer n.
3x = 11n + 2
x = `(11"n" + 2)/3` where n = 2, 5, 8
x = `(11 xx 2 + 2)/3` = 8
x = `(11 xx 5 + 2)/3`
= `(55 + 2)/3`
= `57/3`
= 19
x = `(11 xx 8 + 2)/3`
= `(88 + 2)/3`
= `90/3`
= 30.
∴ x = 8, 19, 30, ...
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