Question

Solve the following systems of equations graphically:

3x + y + 1 = 0

2x − 3y + 8 = 0

Answer 1

The given equations are

3x + y + 1 = 0 ....(1)

2x − 3y + 8 = 0    ...(2)

Putting x = 0 in equaiton (1) we get

`=> 3 xx 0 + y = -1`

`=> y = -1`

`x= 0 ,  y = -1`

Putting y = 0 in equation (1) we get

=> 3x + 0 = -1

=> x = -1/3

x = -1/3 , y = 0

Use the following table to draw the graph.

x	0	-1/3
y	-1	0

Draw the graph by plotting the two points A(0, -1) and B(-1/3, 0) from table

Graph of the equation (2)

2x - 3y = -8   ...(ii)

Putting x = 0 in equation (2) we ge

`=> 2 xx 0 - 3y =  -8`

=
> x = -4

x = -4, y = 0

Use the following table to draw the graph.

x	0	-4
y	8/3	0

Draw the graph by plotting the two points C(0, 8/3) and D(-4,0) from table.

The two lines intersect at points P(-1,2)

Hence x = -1, y = 2 is the solution.