Advertisements
Advertisements
प्रश्न
Solve the following:
Calculate Q1, D4, and P26 for the following data.
| 18, 24, 45, 29, 4, 7, 28, 49, 16, 26, 25, 12, 10, 9, 8 |
उत्तर
Q1 = size of 1`((n+1)/4)^"th observation"`
Q1 = size of 1`((15+1)/4)^"th observation"`
Q1 = Size of 1 `(16/4)^"th observation"`
Q1 = Size of 1(4)th observation
Size of the 4th observation = 9
Q1 = 9
D4 = Size of 4 `((n+1)/10)^"th observation"`
D4 = Size of 4`((15+1)/10)^"th observation"`
D4 = Size of 4`(16/10)^"th observation"`
D4 = Size of 4(1.6)th observation
= Size of 6.4th observation
= Size of 6th observation + 0.4 (7th observation – 6th observation)
= 12 + 0.4 (16 - 12)
= 12 + 0.4 (4)
= 12 + 1.6
= 13.6
D4 = 13.6
P26 = Size of 26`((n+1)/100)^"th observation"`
P26 = Size of 26`((15+1)/100)^"th observation"`
P26 = Size of 26`(16/100)^"th observation"`
= size of 26 (0.16)th observation
= Size of 4.16th observation
= size of 4th observation + 0.16(5th observation - 4th observation)
= 9 + 0.16 (10 - 9)
= 9 + 0.16(1)
= 9 + 0.16
= 9.16
P26 = 9.16
APPEARS IN
संबंधित प्रश्न
Give the correct option:
Statements related to partition values that are correct.
- Exact divisions of percentiles into 100 parts gives 99 points
- Deciles have total 9 parts
- Quartiles are shown by Q1, Q2 and Q3
- symbolically, percentiles and Deciles are shown by P and D
Choose the correct pair:
| Group A | Group B |
| 1) Quartiles | a) Dj = size of j`((n + 1)/10) ^"th Observation"` |
| 2) Deciles | b) `"P"_k = l +(((kn)/100 – cf)/f) xx "h"` |
| 3) Percentiles | c) `"Q"_i = l +((("in")/4 – cf)/f) xx "h"` |
Give economic term:
Procedure for dividing the data into equal parts.
State with reasons whether you agree or disagree with the following statement:
Partition values have application only in theory but not in practice.
State with reasons whether you agree or disagree with the following statement:
Average can misinterpret the representative value.
Solve the following :
Calculate of Q3, D5, and P35 for the given data
| Income (in lakhs ₹) | 1 | 2 | 3 | 4 | 5 | 6 | |
| No. of family | 2 | 5 | 20 | 25 | 15 | 12 | |
A company produces tables which are packed in batches of 100. An analysis of the defective tubes in different batches has received the following information:
| No. of defective tubes | Less than 5 | 5 – 9 | 10 – 14 | 15 – 9 | 20 – 24 | 25 – 29 | 30 and above |
| No. of tubes | 45 | 51 | 84 | 39 | 20 | 8 | 4 |
Estimate the number of defective tubes in the central batch.
