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Solve the following equation and verify the answer: 34(x−1)=x−3 - Mathematics

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प्रश्न

Solve the following equation and verify the answer:

\[\frac{3}{4} (x - 1) = x - 3\]
बेरीज

उत्तर

\[\frac{3}{4} (x - 1) = x - 3\]
\[\Rightarrow \frac{3}{4} \times x - \frac{3}{4} \times 1 = x - 3\] [On expanding the brackets]
\[\Rightarrow \frac{3x}{4} - \frac{3}{4} = x - 3\]
\[\Rightarrow \frac{3x}{4} - x = - 3 + \frac{3}{4}\] [Transposing x to the L.H.S. and `-3/4` to the R.H.S.]
\[\Rightarrow \frac{3x - 4x}{4} = \frac{- 12 + 3}{4}\]
\[\Rightarrow \frac{- x}{4} = \frac{- 9}{4}\]
\[\Rightarrow \frac{- x}{4} \times \left( - 4 \right) = \frac{- 9}{4} \times \left( - 4 \right)\]  [Multiplying both the sides by -4]
or, x = 9
Verification:
Substituting x = 9 on both sides:
\[L . H . S . : \frac{3}{4}\left( 9 - 1 \right) \]
\[ = \frac{3}{4}(8) \]
\[ = 6 \]
\[R . H . S . : 9 - 3 = 6\]
L.H.S. = R.H.S.
Hence, verified.
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पाठ 9: Linear Equation in One Variable - Exercise 9B [पृष्ठ १४३]

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आर एस अग्रवाल Mathematics [English] Class 6
पाठ 9 Linear Equation in One Variable
Exercise 9B | Q 26 | पृष्ठ १४३

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